1.

Why is ICl more reactive than `I_(2)` ?

Answer» When molten Icl is electrolysed, `I^(+)` ion is formed at cathode which gets reduced to `I_(2)`
`underset(("Molten"))(2ICl) harr underset(("Cathode"))I^(+)+underset(("Anode"))[Icl_(2)]^(-) , 2I^(+)+2e^(-) to I_(2)`


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