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With the help of thermochemical equations given below, determine `Delta_(r )H^(Θ)` at `298 K` for the following reaction: `C("graphite")+2H_(2)(g) rarr CH_(4)(g),Delta_(r )H^(Θ) = ?` `C("graphite")+O_(2)(g) rarr CO_(2)(g), Delta_(r )H^(Θ) = -393.5 kJ mol^(-1)` ...(1) `H_(2)(g) +1//2O_(2)(g) rarr H_(2)O(l)`, `Delta_(r )H^(Θ) = -285.8 kJ mol^(-1)` ...(2) `CO_2(2)(g)+2H_(2)O(l) rarr CH_(4)(g)+2O_(2)(g)`, `Delta_(r )H^(Θ) = +890.3 kJ mol^(-1)` ...(3)A. `+ 78.8kJ mol^(-1)`B. `+144.0kJ mol^(-1)`C. `- 74.8kJ mol^(-1)`D. `-144.0kJ mol^(-1)` |
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Answer» Correct Answer - c |
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