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With the help of Valence Bond theory account for hybridisation, geometry and magnetic property of [Ni(CN)_(4)]^(2-) complex ion [Z" for "Ni=28] |
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Answer» Solution :In the given COMPLEX ion central metal is nickel with electronic configuration `[Ar]^(18)3d^(8)4s^(2)` Nickel is in `+2` oxidation state thereofre electronic configurations is `Ni^(+2)`  In the given complex, `CN^(-)` is a strong ligand. On the approach of strong ligand the unpaired 3d electron will get pair up. As a RESULT one d - orbital becomes vacant.  The one vacant 3d orbital, one vacant 4s orbital and two vacant 4P orbitals hybridize to give four hybrid orbitals.  Four pairs of electrons one from each `CN-` molecule occupy the four hybridized orbitals.  Due to `dsp^(2)` hybridization the complex ion is square planar in shape. There are no unpaired electrons in the complex so it is diamagnetic. Hybridisation `-dsp^(2)` Geometrical shape - Square planar Magnetic property - Diamagnetic |
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