InterviewSolution
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InterviewSolution
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With what minimum acceleration can a fireman slide down a rope whose breaking strength is `(2//3)` of his weight?A. `(g)/(2)`B. `(2)/(3)g`C. `(3)/(2)g`D. `(g)/(3)` |
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Answer» Correct Answer - D Net downward force in the string, ma = mg - T But `T_("min") = (2)/(3) mg " " therefore " "ma_("min") = mg - (2)/(3) mg a_("min") = g - (2)/(3) g = (g)/(3)` |
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