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Without using distance formula, show that points `(2, 1)`, `(4, 0)`, `(3, 3)`and `(3, 2)`are the vertices of a parallelogram. |
Answer» Please refer to video for the figure.Here, slope of `AB = (0-(-1))/(4-(-2)) = 1/6` Slope of `BC = (3-0)/(3-4) = -3` Slope of `CD = (2-3)/(-3-3) = 1/6` Slope of `DA = (2-(-1))/(-3-(-2)) = -3` As, slope of `AB` = slope of `CD` and slope of `BC` = slope of `AD` It means, `AB||CD` and `BC||AD` So, ABCD is a parallelogram. |
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