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wo blocks of 7 kg and 5 kg are connectedeavy rope of mass 4 kg. An upward force of 2applied as shown in the diagram. The tent the top of heavy rope at point P is:g = 10 m/s2)200N7kgboooooo4kg5kg) 2.27 N(2) 112.5 N (3) 87.5 N(4) 3 |
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Answer» Given, Mass of top block (m1) = 5 kg Mass of lower block (m2) = 7 kg Mass of rope (mw) = 4 kg The total mass of the system (m) = 5+ 4+ 7 16 kg Force = 200 N total downward force = mg = 16 × 10 = 160 N thus, the correct option is B the accereleration of the system, According to the equation F=ma => F - mg = ma (g= 10 m/s^2 => 200 - 16 × 10 = 16 a => 200 - 160 = 16 a => 40/16 = a => 2.5 = a ∴ acceleration of the system = 2.5 m/s^2The tension at the top of the heavy rope is of mass mass = 5+ 4 = 9 kg a = 2.5 m/s^2 T= ma + mg =m (a+ g) = 9 × 12.5 = 112.5 N Tension at the midpoint of the rope, m = 4 kg T = m(a +g) = 4 × 12.5 = 50 N Tension at the lower endpoint of the rope m = 7kg T = m (a+g) = 7 × 12.5 = 87.5 N 87.5 N is the right answer 87.5 N is the right answer |
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