wo blocks of 7 kg and 5 kg are connectedeavy rope of mass 4 kg. An upward force of 2applied as shown in the diagram. The tent the top of heavy rope at point P is:g = 10 m/s2)200N7kgboooooo4kg5kg) 2.27 N(2) 112.5 N (3) 87.5 N(4) 3

wo blocks of 7 kg and 5 kg are connectedeavy rope of mass 4 kg. An upw

1.	wo blocks of 7 kg and 5 kg are connectedeavy rope of mass 4 kg. An upward force of 2applied as shown in the diagram. The tent the top of heavy rope at point P is:g = 10 m/s2)200N7kgboooooo4kg5kg) 2.27 N(2) 112.5 N (3) 87.5 N(4) 3
Answer» <p>Given,</p><p>Mass of top block (m1) = 5 kg</p><p>Mass of lower block (m2) = 7 kg</p><p>Mass of rope (mw) = 4 kg</p><p>The total mass of the system (m) = 5+ 4+ 7</p><p> 16 kg</p><p>Force = 200 N</p><p>total downward force = mg</p><p> = 16 × 10</p><p> = 160 N</p><p>thus, the correct option is B</p><p>the accereleration of the system,</p><p>According to the equation</p><p>F=ma</p><p>=> F - mg = ma (g= 10 m/s^2</p><p>=> 200 - 16 × 10 = 16 a</p><p>=> 200 - 160 = 16 a</p><p>=> 40/16 = a</p><p>=> 2.5 = a</p><p>∴ acceleration of the system = 2.5 m/s^2The tension at the top of the heavy rope is of mass</p><p>mass = 5+ 4 = 9 kg</p><p>a = 2.5 m/s^2</p><p>T= ma + mg</p><p> =m (a+ g)</p><p> = 9 × 12.5</p><p> = 112.5 N</p><p>Tension at the midpoint of the rope,</p><p>m = 4 kg</p><p>T = m(a +g)</p><p> = 4 × 12.5</p><p> = 50 N</p><p>Tension at the lower endpoint of the rope</p><p> m = 7kg</p><p>T = m (a+g)</p><p> = 7 × 12.5</p><p> = 87.5 N</p> <p>87.5 N is the right answer</p> <p>87.5 N is the right answer </p>