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Word Problems:- 1. An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach -350 m deep from the ground? 2. The temperature of town A at 4 p.m. was 41°C above zero. The temperature recorded at 10 p.m. was 29°C. If the temperature falls at a constant rate per hour, find the fall in temperature per hour. |
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Answer» Answer: 1) 1 hour 2) 2 hour Step-by-step explanation: 1) Given :- Initial height = 10m Final depth = 350m Note :- Distance descended in denoted by a '-ve' integer. Now :- Distance to be descended : => x = (-350) - (10) => x = -350 - 10 => x = -360m So, Total distance to be descended by the elevator is -360m. Thus, To descend -360m, time taken by elevator is : => x = -360/-6 => x = 60 We know that :- 60 minutes = 1 hour Therefore answer = 1 hour 2) Ans :- => The FALL in TEMPERATURE is 2° per hour. => Time taken fall in temperature is 10 - 4 = 6 => Temperature fall in 6 hours = 41 - 29 = 12 => Fall in temperature hour = 12/6 = 2 hour Ans. |
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