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Work done by a force `F=(hati+2hatj+3hatk)` acting on a particle in displacing it from the point `r_(1)=hati+hatj+hatk` to the point `r_(2)=hati-hatj+hat2k` isA. `-3 J`B. `-1 J`C. zeroD. 2 J |
Answer» Correct Answer - B (b) `W=F.s=F.(s_(2)-s_(1))` `=(hati+2hatj+3hatk).[(hati-hatj+2hatk)-(hati+hatj+hatk)]` `=(hati+2hatj+3hatk).(-2hatj+hatk)=-4+3=-1J` |
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