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Work done in increasing the size of a soap bubble from a radius of 3cm to 5cm is nearly (Surface tension of soap solution `=0.03Nm^-1`)A. (a) `0.2pimJ`B. (b) `2pimJ`C. (c) `0.4pimJ`D. (d) `4pimJ` |
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Answer» Correct Answer - C W=Tx change in surface area `W=2T4pi[(5^2)-(3)^2]xx10^4` `=2xx0.03xx4pi[25-9]xx10^-4J=0.4pixx10^3J` `=0.4pimJ` |
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