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Work done in time t on a body of mass m which is accelerated from rest to a speed v in time `t_(1)` as a function of time t is given bA. `(1)/(2)m(v^(2))/(t_(1)^(2))t^(2)`B. `(1)/(2)((mv)/(t_(1)))^(2)t^(2)`C. `m(v)/(t_(1))t^(2)`D. `(1)/(2)m(v)/(t)t^(2)` |
Answer» Correct Answer - A (a) Work done `="Force"xx"displacement"` F=ma and `s=(1)/(2)at^(2)` Using,`" " s=ut+(1)/(2)at^(2)` `:. " " W=maxx(1)/(2)at^(2)=(1)/(2)ma^(2)t^(2)` `=(1)/(2)m((v)/(t_(1)))^(2)t^(2)=(1)/(2)m(v^(2))/(t_(1)^(2))t^(2) " " ("Using" a=(v)/(t_(1)))` |
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