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Work done on a system when one mole of an an ideal gas at 500 K is compressed isothermally and reversibly to 1/10th of its original volume. (R = 2cal)A. `500 kcal`B. `1.51 kcal`C. `-23.03 kcal`D. `2.303 kcal` |
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Answer» Correct Answer - D `W=-2.303 nRT log (V_(2))/(V_(1))` `=-2.303xx1xx2xx500 log (1)/(10)` `=(-2.303xx1000xlog10^(-1))/(1000)kJ` `=+2.303 kJ` |
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