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Work is said to be done by a force acting on a body, provided the body is displaced actually in any direction except in a direction perpendicular to the direction of the force. Mathematically, `W=vec(F). vec(c)=Fs cos theta`, Whereas energy is capacity of a body to do the work, power is the rate at which the body can do the work. `P=(W)/(t)=vec(F).(vec(s))/(t)=vec(F). vec(upsilon)` Both, work and energy are measured in joule and power is measured in watt. With the help of the comprehension given above, choose the most appropriate alternative for each of the following question `:` A truck draw a tractor of mass `1000 kg ` at a steady rate of `20 ms ^(-1)` on a level road. The tension in the coupling is `2000N`. Power spent on the tractor isA. `40 W`B. `20 W`C. ` 20 kW`D. `40 kW` |
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Answer» Correct Answer - D Force applied `=` tension is coupling `=2000N` As `P=Fupsiloncos theta` `:. P= 2000 xx 20 cos 0^(@)= 40000 W = 40 k W ` |
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