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Work out the equation of the line which has a gradient of 3 and passes through the point (-1,3) Please help!

Answer»

3x-y+6=0Step-by-step explanation: Let the point be P(-1,3) = (x1,y1)SINCE gradient is 3, which is ;m = 3FORMULA TO FIND THE EQUATION OF A LINE WITH SLOPE.y-y1 = m(x-x1)y-3 = 3(x+1)y-3 = 3x+33x-y+3+3=03x-y+6=0



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