Write a program in java to evaluate the arithmetic expression where a=

1.	Write a program in java to evaluate the arithmetic expression where a=3, b=4 and c=7 and f =a+b*c. find the value of f.find value with steps
Answer» Answer: p = ++a + --a ⇒ p = 8 + 7 ⇒ p = 15 q -= p ⇒ q = q - p ⇒ q = 0 - 15 ⇒ q = -15 Explanation: Simple expressions A simple expression is a literal, variable name, or method call. No operators are involved. Here are some examples of simple expressions: 52 // integer literal age // variable name System.out.println("ABC"); // method call "Java" // string literal 98.6D // double precision floating-point literal 89L // long integer literal A simple expression has a type, which is either a primitive type or a reference type. In these examples, 52 is a 32-bit integer (INT); System.out.println("ABC"); is void (void) because it returns no value; "Java" is a string (String); 98.6D is a 64-bit double precision floating-point value (double); and 89L is a 64-bit long integer (long). We don't know age's type. Experimenting with jshell You can easily try out these and other simple expressions using jshell. For example, enter 52 at the jshell> prompt and you'll receive something like the following output: $1 ==> 52 $1 is the name of a scratch variable that jshell CREATES to store 52. (Scratch variables are created whenever literals are ENTERED.) Execute System.out.println($1) and you'll see 52 as the output. You can run jshell with the -v command-line argument (jshell -v) to generate VERBOSE FEEDBACK. In this case, entering 52 would result in the following message, revealing that scratch variable $1 has int (32-bit integer) type: \| created scratch variable $1 : int Next, try entering age. In this case, you'll probably receive an error message that the symbol was not found. The Java Shell assumes that age is a variable, but it doesn't know its type. You would have to include a type; for example, see what happens if you enter int age. hope it helped you friend if it helps you mark it as brainliest Happy learning

Write a program in java to evaluate the arithmetic expression where a=3, b=4 and c=7 and f =a+b*c. find the value of f.find value with steps

Answer»

Answer:

p = ++a + --a

⇒ p = 8 + 7

⇒ p = 15

q -= p

⇒ q = q - p

⇒ q = 0 - 15

⇒ q = -15

Explanation:

Simple expressions

A simple expression is a literal, variable name, or method call. No operators are involved. Here are some examples of simple expressions:

52 // integer literal

age // variable name

System.out.println("ABC"); // method call

"Java" // string literal

98.6D // double precision floating-point literal

89L // long integer literal

A simple expression has a type, which is either a primitive type or a reference type. In these examples, 52 is a 32-bit integer (INT); System.out.println("ABC"); is void (void) because it returns no value; "Java" is a string (String); 98.6D is a 64-bit double precision floating-point value (double); and 89L is a 64-bit long integer (long). We don't know age's type.

Experimenting with jshell

You can easily try out these and other simple expressions using jshell. For example, enter 52 at the jshell> prompt and you'll receive something like the following output:

$1 ==> 52

$1 is the name of a scratch variable that jshell CREATES to store 52. (Scratch variables are created whenever literals are ENTERED.) Execute System.out.println($1) and you'll see 52 as the output.

You can run jshell with the -v command-line argument (jshell -v) to generate VERBOSE FEEDBACK. In this case, entering 52 would result in the following message, revealing that scratch variable $1 has int (32-bit integer) type:

| created scratch variable $1 : int

Next, try entering age. In this case, you'll probably receive an error message that the symbol was not found. The Java Shell assumes that age is a variable, but it doesn't know its type. You would have to include a type; for example, see what happens if you enter int age.