Saved Bookmarks
| 1. |
Write an arithmetic sequence with first team 3. |
|
Answer» Answer: FIRST TERM of the sequence is 10 and common difference is 3. a1 = 10 and d = 3 Next term = a2=a1+d=10+3=13 a3=a2+d=13+3=16 Thus, first three terms of the sequence are 10, 13 and 16. Let 100 be the nth term of the sequence. an=a1+(n−1)d 100=10+(n−1)3 90=(n−1)3 n−1=30 n=31, which is a WHOLE number. Therefore, 100 is the 31ST term of the sequence |
|