InterviewSolution
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InterviewSolution
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Write down the formula for distance between two consecutive bright fringes or two consecutive dark fringes. |
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Answer» Solution :For fringes of constructive interference (bright), `x_(n)=(nlamdaD)/(d)` for `n^(TH)` ORDER of bright fringe. Now for `(n+1)^(th)` order of bright fringe. `x_(n+1)=((n+1)lamdaD)/(d)` DISTANCE between TWO consecutive bright fringes `x._(n+1)-x._(n)=(2n+3)(lamdaD)/(2d)-(2n+1)(lamdaD)/(2d)` `=(lamdaD)/(2d)[2n+3-2n-1]` `=(lamdaD)/(2d)[2]` `:.beta=(lamdaD)/(d)` Hence, the distance between two consecutiv bright or the distance between two consecutiv dark fringe (s) are same. This is the equation width of fringe also. |
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