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Write in polar form -2i |
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Answer» Answer: 2(cos 0+ isin 0) Step-by-step explanation: -2i we know that the POLAR form of a complex NUMBER is r(cos teete+i SIN teeta) [where r=√x^2+y^2 and teeta = tan INVERSE (y/x)] -2i=0-2i therefore x=0 and y=-2 r=√(0)^2+(-2)^2 =√0+4 =√4 =2 teeta = tan inverse (-2/0) = tan inverse (0) = tan inverse (tan 0) teeta = 0 since,r(cos teeta+i sin teeta) 2(cos 0 + sin 0) |
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