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Write Lewis structure of `O_(2)^(-)` ion and find out oxidation state of each oxygen atom? What is the average oxidation state of oxygen in this ion?

Answer» The Lewis structure of `O_(2)^(-)` is `:overset(..)underset(.)(O)-ddot(O):^(-)`
Oxygen atom carrying no charge has six electrons, so its oxidation number is zero. But oxygen atom carrying -1 charge has 7 electrons, so its oxidation number is -1 Average oxidation number of each oxygen atom `= (1)/(2)`
`O_(2)^(-) = 2x =- 1`
`x =- (1)/(2)`


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