1.

Write order and degree (if defined)of differential equations: \(\cfrac{d^4y}{dx^3}-cos\left(\cfrac{d^3y}{dx^3}\right)=0\)(d4y/dx4)-cos(d3y/dx3)=0

Answer»

The order of a differential equation is the order of the highest derivative involved in the equation. So the 

order comes out to be 4 as we have \(\cfrac{d^4y}{dx^4}\) and the degree is the highest power to which a derivative is raised. 

But when we open the Cos x series, we get \(1-\cfrac{x^2}{2!}+\cfrac{x^2}{2!}-\cfrac{x^6}{6!}+-----\) ,This leads to an undefined power on the highest derivative. Therefore the deg9ee of this function becomes undefined. 

So the answer is 4, not defined



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