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Write the 150th term of 2 4 6 8 10 |
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Answer» Given Sequence is ⇒First TERM (a) = 2 ⇒Common difference (d) = a₂-a₁ = 4 -2 = 2 To FIND ⇒Number of term 150 Formula ⇒Tₙ = a+(n-1)d Now put the VALUE ⇒T₁₅₀ = 2 + (150-1)×2 ⇒T₁₅₀ = 2 + 149×2 ⇒T₁₅₀ = 2+298 ⇒T₁₅₀ = 300 Answer ⇒T₁₅₀ = 300 More Information ⇒Nth term = a+(n-1)d ⇒Sum = n/2{2a+(n-1)d} or ⇒Sum = n/2(a+l) where l = a + (n-1)d |
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