1.

Write the degree of the DE y’ = 2xy. [0, 1, 2, 3] Express y’ = 2xy in the form Mdx = Ndy. Where M is a function of x and N is the function of y. Solve y’ = 2xy, y(0) = 1

Answer»

1. Degree = 1

2. We have, \(\frac{dy}{dx}\) = 2xy ⇒ \(\frac{dy}{y}\) = 2xdx, which is of the form Mdx = Ndy.

3. Solution is ∫\(\frac{dy}{y}\) = 2∫xdx ⇒ log|y| = x2 + c

Given y(0) = 1 ⇒ log|1| = 0 + c ⇒ c = 0

⇒ log|y| = x2 ⇒ y = ex2.



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