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Write the domain and range of function f(x) given by f(x) = 1/√(x-|x|).f(x) = \(\frac{1}{\sqrt{x-|x|}}\). |
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Answer» Given, f(x) = 1/√(x-|x|) For f(x) to be defined, x-|x|>0 But x-|x|≤0 So, f(x) does not exist.. Therefore, D(f) = R(f) = ϕ |
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