1.

Write the electronic configuration of the elements with atomic numbers 61 ,91, 101 and 109 .

Answer»

Solution :`Z= 61` ( Promethium , P m ) , E.C.`= [Xe]^(54) 4f^(5) 5d^(0)6S^(2)`
`Z=91` ( Protactium, Pa) , E.C. `= [rN]^(86) 5F^(2) 6D^(1) 7 S^(1)`
`Z= 101 ` ( MENDELEVIUM, Md), E.C. `= [Rn]^(86) 5f^(13) 6d^(0) 7S^(2)`
`Z =109` ( Meitnerium, Mt ) , E.C.`= [ Rn]^(86) 5f^(14) 6d^(7) 7s^(2)`


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