1.

Write the equation for the reaction of zinc with hydrochloric acid and balance the equation. Find out the number of molecules of hydrogen gas produced in this reaction, when 1 mole of HCl completely reacts at S.T.P. [Gram molar volume is 22.4 liters at S.T.P., Avogadro’s number is 6.023 × 1023 ]

Answer»

Zn + 2HCl → ZnCl2 + H2 

  • In the reaction 2 moles of HC/ produce 1 mole of H2
  • If 1 mole of HCl participate in reaction, Vi mole of hydrogen will be produced. 
  • 1 mole of H2 gas contains 6.023 × 1023 molecules at STP. Number of molecules in 1/2 mole of H2 gas = 6.023 × 1023 × ½ = 3.011 × 1023


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