InterviewSolution
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InterviewSolution
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Write the equation of SHM for the situations show below: |
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Answer» (a) At `t = 0, x = +A` `x = Asin(omegat + phi)` `A = Asin(phi)` `phi = pi//2` `x = A sin (omegat + (pi)/(2)) = Acos(omegat)` (b) At `t = 0, x = -A` `x = A sin(omegat + phi)` `-A = Asin phi` `phi = (3pi)/(2)` `x = A sin(omegat + (3pi)/(2))` `x = -A cos (omegat)` (c) At `t = 0, x = (A)/(2)` `x = A sin (omegat + phi)` `(A)/(2) = A sin (omegat + phi)` `(1)/(2) = sin phi rArr phi = 30^(@), 150` Particle is moving towards the mean position and in negative direction. velocity `v = Aomega cos (omegat + phi)` At `t = 0, v = -ve` hence `v = Aomegacis phi` hence `phi = 150^(@)` `x = A sin(omegat + 150^(@))` (a) `x = Acosoemgat`, (b) `x = -A cosomegat`, (c) `x = Asin(omegat + 150^(@))` |
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