Saved Bookmarks
| 1. |
Write the expression for the half life of a radioactive element. |
|
Answer» Solution :After ONE half LIFE `t=T_(1//2) rArr N= N_(0) //2` USING the RELATION `N= N_(0) e^(-lambda t)` `rArr N_(0) //2 = N_(0) e^(- lambda T_(1//2) )` `rArr 1//2 = e^(-lambda T_(N))` `rArr lambda T_(1//2) = log_(n) 2` `rArr lambda T_(1//2) = 0.693 ` Arriving at `T_(1//2) = (0.693)/(lambda) ` |
|