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Write the following ionic equation in the molecular form if the reactants are chlorides. `2Fe^(3+)+Sn^(2+) to 2Fe^(2+)+Sn^(4+)` |
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Answer» For writing the reactants in moleuclar forms, the requisite number of chloride ions are added. `ubrace(2Fe^(3+)+6Cl^(-))+ubrace(Sn^(2+)+2Cl^(-))` Similarly `8Cl^(-)` ions are added on RHS ot neutralise the charges. `underset(2FeCl_(2))ubrace(2Fe^(2+)+4Cl^(-))+underset(SnCl_(4))ubrace(Sn^(4+)+4Cl^(-))` Thus, the balanced molecular equation is `2FeCl_(3)+SnCl_(2)=2FeCl_(2)+SnCl_(4)` |
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