1.

Write the maximum values of 12 sin x – 9 sin2 x.

Answer»

f(x) = 12sin x - 9(sinx)2

f(x) = - (3sin x - 2)2 + 4

- 1 ≤ sin x ≤ 1

f(x)ϵ-(3[-1,1]-2)2+4 

f(x)ϵ-([-3,3]-2)2+4 

f(x)ϵ-([-5,1])2+4 

f(x)ϵ-[0,25]+4 

f(x)ϵ[-25,0]+4 

f(x)ϵ[-21,4]



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