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| 1. |
Write the maximum values of 12 sin x – 9 sin2 x. |
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Answer» f(x) = 12sin x - 9(sinx)2 f(x) = - (3sin x - 2)2 + 4 - 1 ≤ sin x ≤ 1 f(x)ϵ-(3[-1,1]-2)2+4 f(x)ϵ-([-3,3]-2)2+4 f(x)ϵ-([-5,1])2+4 f(x)ϵ-[0,25]+4 f(x)ϵ[-25,0]+4 f(x)ϵ[-21,4] |
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