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Write the mechanism of the reaction of HI with methoxymethane. |
Answer» Solution :With equimolar AMOUNTS of HI and METHOXYMETHANE, a mixture of methyl ALCOHOL and methyl iodide is obtained. The mechanism is gien as under : If however, excess of HI is used, methyl alcohol formed in STEP 2 is also converted into methyl iodide. This is explained by the following mechanism. ![]()
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