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Write the most probable equation for the rate of reaction giving reason for your answer.Expt. No[A] (mol L-1 )[B2] (mol L-1 )Rate (mol L-1 s-1)10.500.501.6 × 10-420.501.003.2 × 10-431.001.003.2 × 10-4 |
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Answer» From an examination of above data, it is clear that when the concentration of B2 is doubled, the rate is doubled. Hence the order of reaction with respect to B2 is one. Further when concentration of A is doubled, the rate remains unaltered. So, order of reaction with respect to A is zero. OR The probable rate law for the reaction will be dx/xt = k[B2]1 [A]0 = k[B2]1 Alternatively Rate = k[B2]x 1.6 × 10-4 = k[0.5]x 3.2 × 10-4 = k[1]x On dividing we get x = 1 Rate = k[A]0 [B2]1 = k[B2] |
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