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Write the redox reactions using half equations.Zn(s) + PbCl2(aq) → Pb(s) + ZnCl2(aq)In the reactions given above, mention (i) Which reactant is oxidized? To what ?(ii) Which reactant is the oxidizer?(iii) Which reactant is reduced? To what?(iv) Which reactant is the reducer? |
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Answer» Zn → Zn2+ + 2e– (oxidation), Pb2+ → 2e– +Pb (reduction) Zn is oxidized to Zn2+ Pb2+ is reduced to Pb Pb2+ is the oxidizer Zn is the reducer. |
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