1.

Write the redox reactions using half equations.Zn(s) + PbCl2(aq) → Pb(s) + ZnCl2(aq)In the reactions given above, mention (i) Which reactant is oxidized? To what ?(ii) Which reactant is the oxidizer?(iii) Which reactant is reduced? To what?(iv) Which reactant is the reducer?

Answer»

Zn → Zn2+ + 2e (oxidation), 

Pb2+ → 2e +Pb (reduction) 

Zn is oxidized to Zn2+ 

Pb2+ is reduced to Pb 

Pb2+ is the oxidizer

Zn is the reducer.



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