1.

Write the structure of the aldehyde, carboxylic acid and ester that yield 4- methylpent -2-en-1-ol

Answer»

SOLUTION :(i) Aldehyde yield 4-methylpent-2-en-1-ol is,
`CH_3- UNDERSET(CH_3)underset(|)(CH) - CH = CH - CHO`
(ii) ACID yicld 4-methylpent-2-en-1-ol is,
`CH_3 - underset(CH_3)underset(|)(CH) - CH = CH - COOH`
(iii) ESTER yield 4-methylpent-2-en-1-ol is,
`CH_3 - underset(CH_3)underset(|)(CH) -CH = CH- COOC_2 H_5`
The above shown compounds undergo REDUCTION reaction to yield 4 - methylpent - 2- en - 1 - ol.
`CH_3 -underset(CH_3)underset(|)(CH) - CH = CH - CH_2 - OH`


Discussion

No Comment Found

Related InterviewSolutions