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(x+1)(x+2)(x+3)(x+6)-3x^2 |
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Answer» WAY to do it is to WRITE (x+2)(x+3)=x2+6x+6−x, (x+1)(x+6)=x2+6x+6+x, so (x+2)(x+3)(x+1)(x+6)=(x2+6x+6)2−x2 which GIVES that (x+2)(x+3)(x+1)(x+6)−3x2=(x2+6x |
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