1.

(x+2) and (x-1) are factors of polynomial 10x²+Px+q then find p/q.​

Answer»

Answer:

10(-2)²+(-2P)+q=0

10(4)-2p+q=0

40-2p+q=0

40=2p-q

2p-q=40............1

10(1)²+p+q=0

10+p+q=0

p+q=-10..............2

adding 1 and 2

p+q+2p-q=40+(-10)

p+2p=40-10

3p=30

p=30/3

p=10

putting VALUE of p in eq 1

2p-q=40

2(10)-q=40

20-q=40

20-40=q

q= -20


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