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X^2+sinx/xcosx find the derivation of |
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Answer» -step explanation:HIU just NEED to follow the. u/V rule of differentiationwhich isu= x^2+sinxv= xcosx= (u)'v - (v)'u / (v)^2=( 2x+cosx).xcosx - (x^2+sinx). (cosx-xsinx)------------------------------------------------(xcosx)^2=.( 2x^2cosx+xcos^2x)- (cosx^3-xsinx^3+sinx.cosx-xsin^2x)--------------------------------------------------------(xcosx)^2that was your answerhope it HELPS you........................................mark brainliest.................................✌️ |
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