1.

X= 2t^3 + t^2+ t+2find the acceleration at 2 sec​

Answer»

POSITION of the particle x=2t

2

−t

3

VELOCITY V=

dt

dx

=4t−3t

2

Acceleration a=

dt

dv

=4−6t

So, a( at t=2 s)=4−6×2=−8 m/s

2

Since, acceleration is DEPENDING on the time. SO, acceleration is not constant.


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