InterviewSolution
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`(x+3)^(2).(x+4)^(3).(x+5)^(4)` |
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Answer» माना `y=(x+3)^(2)(x+4)^(3)(x+5)^(4)` `rArr" "logy=log{(x+3)^(2)(x+4)^(3)(x+5)^(4)}` `=2log(x+3)+3log(x+4)+4log(x+5)` दोनों पक्षों का x के सापेक्ष अवकलन लेने पर `(1)/(y)(dy)/(dx)=(2)/(x+3)+(3)/(x+4)+(4)/(x+5)` `rArr" "(dy)/(dx)=y[(2)/(x+3)+(3)/(x+4)+(4)/(x+5)]` `rArr" "(dy)/(dx)=(x+3)^(2)(x+4)^(3)(x+5)^(4)[(2)/(x+3)+(3)/(x+4)+(4)/(x+5)]` |
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