1.

(x+3)2 + (y-2)2=0 then xy= ​

Answer»

ANSWER:

(x+3)2 = 2X + 6 ; (y-2)2 = 2y - 4. So, (x+3)2 + (y-2)2 = 0 ; 2x+6 + 2y -4 = 0; .

Step-by-step explanation:

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