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(x+3)2 + (y-2)2=0 then xy= |
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Answer» (x+3)2 = 2X + 6 ; (y-2)2 = 2y - 4. So, (x+3)2 + (y-2)2 = 0 ; 2x+6 + 2y -4 = 0; . Step-by-step explanation: ✌️✌️✌️✌️✌️ |
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