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X/3 +y/4=1 , 5x/6-y/3=-7 find value of x and y by substituting method |
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Answer»
x/3+y/4=1,5x/6-y/3=-7 4x+3y=12,5x-2y=-42(by LCM) y=12-4x.........eq.1 put eq.1 in 5x-2y=-42 we get:5x-2(12-4x)=-42 5x-24+8x=-42 5x+8x=-42+24 13x=-18 x=-18/13 y=12-4*(-18/13) =-11.07..... |
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