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X=4 and y=2 is the solution ofthe pair of linear equations. a. x+y=6 , x-y=1b.x+y=6, 2x+3y=9c. x-y=2 , 2x+y=10d. x+y=6 , x-y=-2 |
Answer» Direct Answer:Option C Given:★ The value of x and y as 4 and 2 respectively. ★ Four PAIRS of linear EQUATIONS namely: a. x + y = 6, x - y = 1 b. x + y = 6, 2x + 3y = 9 c. x - y = 2, 2x + y = 10 d. x + y = 6, x - y = -2 To Find:Which pair of the given linear equations will have x = 4 and y = 2 as their solutions. Solution:In order to find the pair of linear equations with x = 4 and y = 2 as their solutions, we need to substitute the value of x and y with the given values and check whether the answer we get on solving is equal to the RHS. Option a No.1 x + y = 6 x = 4 , y = 2 Substituting the values into the LHS, 4 + 2 = 6 LHS = RHS. No.2 x - y = 1 Substituting the values into the LHS, 4 - 2 = 2 2 ≠ 1 LHS ≠ RHS The given values are not the solutions of the given pair of equations. Option b No.1 x + y = 6 Substituting the values into the LHS, 4 + 2 = 6 LHS = RHS. No.2 2x + 3y = 9 Substituting the values into the LHS, (2 x 4) + (3 x 2) = 8 + 6 = 14 14 ≠ 9 LHS ≠ RHS The given values are not the solutions of the given pair of equations. Option c No.1 x - y = 2 Substituting the values into the LHS, 4 - 2 = 2 LHS = RHS No.2 2x + y = 10 Substituting the values into the LHS, (2 x 4) + 2 = 8 + 2 = 10 LHS = RHS The given values are the solutions of the given pair of equations. Option d No.1 x + y = 6 Substituting the values into the LHS, 4 + 2 = 6 LHS = RHS No.2 x - y = -2 Substituting the values into the LHS, 4 - 2 = 2 LHS ≠ RHS The given values are not the solutions of the given pair of equations. From the above observations, we can CONCLUDE that Option C is the pair of linear equations that has the given values of x and y as the solution. a. x + y = 6, x - y = 1 b. x + y = 6, 2x + 3y = 9 c. x - y = 2, 2x + y = 10 ✔ d. x + y = 6, x - y = -2 |
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