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X+9, x-6 and 4 are three consecutive terms of a G.p |
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Answer» terms of GP = 25 ,10 ,4 a = x +9 b = x -6 C = 4 If a,b,c are CONSECUTIVE terms of GP b^2 = ac
(x - 6 ) ^2 = ( x+ 9 ) × 4 x^2 - 12 x + 36 = 4x + 36 x^2 - 16 x = 0 x^2 = 16 x x = 16 terms of GP a = 16 + 9 = 25 b = 16 - 6 = 10 c = 4 |
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