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X and Y are points on the side LN of the triangle LMN such that LX = XY = YN. Through X, a line is drawn parallel to LM to meet MN at Z (see figure). Prove that `ar (DeltaLZY) = ar (MZYX)`. |
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Answer» Given X and Y are points on the side LN such as that LX = XY = YN and `XZ || LM` To prove `" " ar (DeltaLZY) = ar (MZYX)` Proof Since, `DeltaXMZ` and `DeltaXLZ` are on the same base XZ and between the same parallel lines LM and XZ. Then, `" " ar (DeltaXMZ) = ar (DeltaXLZ)" "` ...(i) On adding `ar (DeltaXYZ)` both sides of Eq. (i), we get `ar (DeltaXMZ) + ar (DeltaXYZ) = ar (DeltaXLZ) + ar (DeltaXYZ)` `rArr` `" " ar (MZYX) = ar (DeltaLZY)" "` Hence proved. |
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