InterviewSolution
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x के सापेक्ष अवकलन कीजिए । `cos(logx+e^(x))` |
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Answer» माना `y=cos(logx+e^(x))` `rArr" "(dy)/(dx)=(d)/(dx)cos(logx+e^(x))` `=-sin(logx+e^(x))(d)/(dx)(logx+e^(x))` `=-sin(logx+e^(x))((1)/(x)+e^(x))` `=(-sin(logx+e^(x))(1+x.e^(x)))/(x)` |
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