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x = Number of structural isomer of C_(4)H_(10)O reacts with PhMgBr to gave as a product.

Answer»

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Solution :`LOG K=logA-(E_(a))/(2.303RT)`
`k=(0.693)/(t_(1//2))=(0.693)/(693)=10^(-3)s^(-1)`
`-3=13-(23.03xx1000)/(2xx2.303xxT),16=(5000)/(T),T=312.5K`


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