Answer:

Factoring x2-10x-600

The first term is, x2 its coefficient is 1 .

The middle term is, -10x its coefficient is -10 .

The last term, "the CONSTANT", is -600

Step-1 : Multiply the coefficient of the first term by the constant 1 • -600 = -600

Step-2 : Find two factors of -600 whose sum equals the coefficient of the middle term, which is -10 .

-600 + 1 = -599

-300 + 2 = -298

-200 + 3 = -197

-150 + 4 = -146

-120 + 5 = -115

-100 + 6 = -94

-75 + 8 = -67

-60 + 10 = -50

-50 + 12 = -38

-40 + 15 = -25

-30 + 20 = -10 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -30 and 20

x2 - 30x + 20x - 600

Step-4 : Add up the first 2 TERMS, pulling out like factors :

x • (x-30)

Add up the last 2 terms, pulling out common factors :

20 • (x-30)

Step-5 : Add up the four terms of step 4 :

(x+20) • (x-30)

Which is the desired factorization

Equation at the end of step

1

:

(x + 20) • (x - 30) = 0

Step-by-step explanation:

hope it helps...