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X2+2x+3=0 find the two roots |
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Answer» Answer: x = -1+2^0.5i and -1-2^0.5i Step-by-step explanation: We will use the quadratic formula for ax^2+ bx+c, where a= 1, b=2 and c=3. The discriminant D = b^2-4ac = -8, which is negative. Hence the SOLUTION will be two COMPLEX number. x=(-2 +- (D)^0.5)/2 = (-2 +- 2*2^0.5i)/2 = -1+2^0.5i and -1-2^0.5i, where i is the IOTA which is equal to (-1)^0.5 |
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