1.

X2+y2=29xy then find the value of 2log (x-y) ​

Answer»

x2+y2=29xyboth SIDE ADD -2xythen x2+y2-2xy=29xy-2xyget (x-y)2=27xyadd LOG both sidelog(x-y)2=log27xylog(x-y)2= 2LOG (x-y)2log(x-y)



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