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xample 8.7 The brakes applied to a carproduce an acceleration of 6 m s^-2 inthe opposite direction to the motion. Ifthe car takes 2 s to stop after theapplication of 'brakes, calculate thedistance it travels during this time.

Answer»

Acceleration a = -6 m/s^2Time t = 2 sFinal velocity v = 0 m/s

Let initial velocity be uLet distance be s

v = u + atSo, 0 = u + (-6)(2)So, u = 12 m/s

Now, s = ut + (1/2) at^2So, s = 12(2) + (1/2)(-6)(2^2)So, s = 24 - 12So, s = 12 m

Thus, distance travelled is 12 m



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