1.

XeF_4 disproportionates in water giving reduced and oxidised products What is the ratio of oxidation states of Xe in the reduced and the oxidised products:

Answer»


SOLUTION :`OVERSET(+4)(6XeF_4)+12H_2Otooverset(0)(4Xe)+overset(+6)(2XeO_3)+24HF+3O_2`


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