`XeF_(6)` on hydrolysis givesA. `XeO_(4)`B. `XeOF_(2)`C. `XeOF_(4)`D. – InterviewSolution

1.	`XeF_(6)` on hydrolysis givesA. `XeO_(4)`B. `XeOF_(2)`C. `XeOF_(4)`D. `XeO_(3)`.
Answer» Correct Answer - D `XeF_(6) + 3H_(2)O rarr XeO_(3) + 6HF`.

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The noble gases which do not form any clatherateA. HeB. NeC. KrD. Xe.
The noble gases which do not form any clatherateA. HeB. ArC. KrD. Xe.
Hybridization and shape of `XeF_(4)` isA. `sp^(3)d`, trigonal bipyramidalB. `sp^(3)`, tetrahedralC. `sp^(3)d^(2)`, square planarD. `sp^(3)d^(2)`, hexagonal.
The state of hybridization of xenon in `XeF_(2)` isA. `sp^(3)`B. `sp^(2)`C. `sp^(3)d`D. `sp^(2)d`
The shape of `XeF_(4)` molecule isA. square planarB. TetrahedralC. OctahedralD. trigonal planar.
Hybridization and shape of `XeF_(4)` isA. `sp^(3)`B. `sp^(3)d`C. `sp^(2)`D. `sp^(3)d^(2)`.
The state of hybridization of xenon in `XeF_(2)` isA. `sp^(2)`B. `sp^(3)d`C. `sp^(2)`D. `sp^(3)d^(2)`.
Which of the following contains maximum number of pairs around Xe atom ?A. `XeF_(4)`B. `XeF_(6)`C. `XeOF_(2)`D. `XeF_(2)`.
The shape of `XeF_(4)` molecule isA. Planar triangularB. TetrahedralC. Square pyramidalD. Square planar.
In `XeF_(2)`, the three lone pairs occupyA. Three equatorial positionB. Two axial and one equatorial positionC. Two equatorial and one axial positionD. Three axial positions.